We have the following table and data:
CREATE TEMPORARY TABLE girls( name text, haircolor text, score INT ); INSERT INTO girls VALUES ('Megan','brunette',9); INSERT INTO girls VALUES ('Tiffany','brunette',5); INSERT INTO girls VALUES ('Kimberly','brunette',7); INSERT INTO girls VALUES ('Hester','blonde',10); INSERT INTO girls VALUES ('Caroline','blonde',5); SELECT * from girls; +----------+-----------+-------+ | name | haircolor | score | +----------+-----------+-------+ | Megan | brunette | 9 | | Tiffany | brunette | 5 | | Kimberly | brunette | 7 | | Hester | blonde | 10 | | Caroline | blonde | 5 | +----------+-----------+-------+ 5 rows in set (0.00 sec) |
Session Variables
MySQL, at least on the versions I've checked, does not support ROW_NUMBER() function that can assign a sequence number within a group, the MySQL session variables can be used to build a workaround. Session variables do not need to be declared first and can be used to do calculations and perform actions based on them. They appear to require initialization. For instance:
@previous_haircolor := haircolor |
This code is executed for each row and stores the value of haircolor column to @current_haircolor variable.
@girl_rank := IF(@previous_haircolor = haircolor, @girl_rank + 1, 1)
In this code, if @previous_haircolor equals the haircolor on the current row we increment rank, otherwise set it to 1. For the first row @previous_haircolor is NULL, so rank is also initialized to 1.
For correct ranking, we need to have ORDER BY haircolor,score DESC
So if we run:
SELECT @previous_haircolor := null; /* Initialize first, or girl_rank will always be 1 */ SELECT name,haircolor,score, @girl_rank := IF(@previous_haircolor = haircolor, @girl_rank + 1, 1) AS girl_rank, @previous_haircolor := haircolor FROM girls ORDER BY haircolor,score DESC |
We get the list of girls ranked by their score within the haircolor group:
+----------+-----------+-------+-----------+----------------------------------+ | name | haircolor | score | girl_rank | @previous_haircolor := haircolor | +----------+-----------+-------+-----------+----------------------------------+ | Hester | blonde | 10 | 1 | blonde | | Caroline | blonde | 5 | 2 | blonde | | Megan | brunette | 9 | 1 | brunette | | Kimberly | brunette | 7 | 2 | brunette | | Tiffany | brunette | 5 | 3 | brunette | +----------+-----------+-------+-----------+----------------------------------+ 5 rows in set (0.00 sec) |
When we have a rank assigned to each girl within her haircolor group, we can request the wanted range:
-- Get top 2 for each haircolor SELECT name, haircolor, score FROM (/*subquery above*/) ranked WHERE girl_rank <= 2; |
So the full query is:
SELECT @previous_haircolor := null; /* Initialize first, or girl_rank will always be 1 */ SELECT name, haircolor, score FROM (SELECT name,haircolor,score, @girl_rank := IF(@previous_haircolor = haircolor, @girl_rank + 1, 1) AS girl_rank, @previous_haircolor := haircolor FROM girls ORDER BY haircolor,score DESC) ranked WHERE girl_rank <= 2; |
Using oracle, SQL Server and PostgreSQL: ROW_NUMBER()
In Oracle, SQL Server and PostgreSQL (version 8.4 and higher) you can achieve the same functionality using ROW_NUMBER function:
SELECT name,haircolor,score FROM (SELECT name,haircolor,score ROW_NUMBER() OVER (PARTITION BY haircolor ORDER BY score DESC) as girl_rank FROM girls) ranked WHERE girl_rank <= 2; |
Nice Article !
I have also work around this topic and created small alternative demo to find N record for each group in MySQL.
Please visit my article.
http://www.dbrnd.com/2015/08/find-top-n-records-for-each-group-in-mysql/